Electronic Devices Circuits Difference Amplifiers Online Exam Quiz
Electronic Devices Circuits Difference Amplifiers GK Quiz. Question and Answers related to Electronic Devices Circuits Difference Amplifiers. MCQ (Multiple Choice Questions with answers about Electronic Devices Circuits Difference Amplifiers
For the circuit given below determine the input common mode resistance.
Options
A : (R1 + R3) || (R2) || + (R4)
B : (R1 + R4) || (R2 + R3)
C : (R1 + R2) || (R3 + R4)
D : (R1 + R3) || (R2 + R4)
Determine the voltage gain for the given circuit known that R1 = R3 = 10k? abd R2 = R4 = 100k?.
Options
A : 1
B : 10
C : 100
D : 1000
If for an amplifier v1 and v2 are the input signals, vc and vd represent the common mode and differential signals respectively, then the expression for CMRR (Common Mode Rejection Ratio) is
Options
A : 20 log (|Ad| / |Ac|)
B : -10 log (|Ac| / |Ad|)2
C : 20 log (v2 – v1 / 0.5(v2 + v1))
D : All of the mentioned
For the difference amplifier as shown in the figure show that if each resistor has a tolerance of ±100 ? % (i.e., for, say, a 5% resistor, ? = 0.05) then the worst-case CMRR is given approximately by (given K = R2/R1 = R4/R3)
Options
A : 20 log [K+1/4?].
B : 20 log [K+1/2?].
C : 20 log [K+1/?].
D : 20 log [2K+2/?].
Determine Ad and Ac for the given circuit.
Options
A : Ac = 0 and Ad = 1
B : Ac ? 0 and Ad = 1
C : Ac = 0 and Ad ? 1
D : Ac ? 0 and Ad ? 1
The problem with the single operational difference amplifier is its
Options
A : High input resistance
B : Low input resistance
C : Low output resistance
D : None of the mentioned
For the difference amplifier which of the following is true?
Options
A : It responds to the difference between the two signals and rejects the signal that are common to both the signal
B : It responds to the signal that are common to the two inputs only
C : It has a low value of input resistance
D : The efficacy of the amplifier is measured by the degree of its differential signal to the preference of the common mode signal
If for an amplifier the common mode input signal is vc, the differential signal id vd and Ac and Ad represent common mode gain and differential gain respectively, then the output voltage v0 is given by
Options
A : v0 = Ad vd – Ac vc
B : v0 = – Ad vd + Ac vc
C : v0 = Ad vd + Ac vc
D : v0 = – Ad vd – Ac vc
For the circuit shown below express v0 as a function of v1 and v2.
Options
A : v0 = v1 + v2
B : v0 = v2 – v1
C : v0 = v1 – v2
D : v0 = -v1 – v2
For the difference amplifier shown below, let all the resistors be 10k? ± x%. The expression for the worst-case common-mode gain is
Options
A : x / 50
B : x / 100
C : 2x / (100 – x)
D : 2x / (100 + x)
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