Automotive Engine Components Design Objective Online Exam Quiz
Automotive Engine Components Design Objective GK Quiz. Question and Answers related to Automotive Engine Components Design Objective. MCQ (Multiple Choice Questions with answers about Automotive Engine Components Design Objective
Calculate the thickness of the piston head by strength criteria, given D=250mm, Pmax=3MPa, ?b= 43N/mm2.
Options
A : 23.92mm
B : 32.85mm
C : 43.3mm
D : 28.593mm
Calculate the thickness of the piston head based on head dissipation, given H=5398.82, k=46.8, (Tc-Te)=200?
Options
A : 45.92mm
B : 30.85mm
C : 43.3mm
D : 35.98mm
Calculate the amount of heat conducted through piston head, when C=0.05, HCV=47×103 KJ/Kg, m=0.25 Kg/Kw/s, BP=8W?
Options
A : 4500KJ
B : 450KJ
C : 470KJ
D : 4700KJ
Bore diameter is 150mm, calculate the thickness based on Held and favary formula?
Options
A : 6.3mm
B : 5.7mm
C : 6.3mm2
D : 5.7mm2
Which are the two types of piston head?
Options
A : Cup and flat type
B : Cup and cone type
C : Cone and bowl type
D : Flat and bowl type
Which are the two criteria for calculating the thickness of the piston head?
Options
A : Heat and Strain
B : Strain and stress
C : Fracture and Strength
D : Strength and Heat dissipation
In the formula th=Dsqrt{frac{3}{16}frac{P_{max}}{sigma_b}}, what is the unit ?b?
Options
A : N/mm3
B : KN/mm2
C : N/mm2
D : N/m2
Which of the mentioned below is used to calculate the thickness of the piston head based on heat dissipation?
Options
A : th=frac{T}{12.56K(T_c-T_e)} × 103
B : H=frac{H}{12.56K(T_c-T_e)} × 103
C : th=frac{H}{12.56K(T_c-T_e)} × 103
D : th=frac{m}{12.56K(T_c-T_e)} × 103
Which of the mentioned below is the Held and favary for the thickness of the piston head?
Options
A : th=0.032D+1.5
B : th=0.032D+1.5d
C : th=0.032D+1.5h
D : th=0.032V+1.5D
Which of the mentioned below is the Grashoff’s formula?
Options
A : th=Dsqrt{frac{3}{16}frac{P_{max}}{T}}316 P max T ? ? ? ? ? ? ?
B : th=Dsqrt{frac{3}{16}frac{P_{max}}{sigma_b}}
C : th=Dsqrt{frac{3}{16}frac{P_{max}}{BP}}
D : th=Dsqrt{frac{3}{16}frac{P_{max}}{IP}}
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