Hardness Test - Torsion Stress for Large Plastic Strains Online Exam Quiz
Hardness Test - Torsion Stress for Large Plastic Strains GK Quiz. Question and Answers related to Hardness Test - Torsion Stress for Large Plastic Strains. MCQ (Multiple Choice Questions with answers about Hardness Test - Torsion Stress for Large Plastic Strains
A torsion test provides a more fundamental study of the plasticity of the metal than the tension test.
Options
A : TRUE
B : FALSE
C : -
D : -
For calculating the modulus of rupture from the thin-walled hollow cylinder, the diameter to wall thickness ratio should be in the order of __
Options
A : 20-Oct
B : 50-100
C : 2-Jan
D : 1000-1500
In the torsion test, the obtained data are with respect to ___
Options
A : stress vs. strain
B : shear stress vs. strain
C : shear stress vs. Shear strain
D : twisting moment vs. Angle of twist
Match the correct order of the temperature from the following diagram?^
Options
A : T1>T2>T3
B : T1<T2<T3
C : T2>T1>T3
D : T3>T1>T2
The brittle fracture in the torsion test results in __ geometry.
Options
A : flat facet
B : helical shape
C : cup and cone
D : shear fracture
The maximum shear stress for a solid cylindrical bar having diameter D, and torsional moment equal to M will be ___
Options
A : 16M/?D3
B : 16M/?D4
C : 8M/?D
D : MD
The typical test temperature in the hot torsion testing is ___
Options
A : just above room temperature
B : below room temperature
C : above 0.6 Tm; where Tm is melting point
D : just below the melting point
Which of the following statement is correct?
Options
A : Torsion test plastic deformation starts much before compared to tension test
B : tension test failure of material occurs much faster than the torsion test
C : The shear stress value in the torsion test is higher than the tension test
D : The total amount of plastic deformation possible is much higher in tension test than torsion test
Which of the following statement is not correct with respect to the torsion test?
Options
A : ?1 = -?3; ?2 = 0
B : ?max = 2?1/2 = ?max
C : ?max = ?1; ?2=?3 = -?1/2
D : ? max = ?1-?3 = 2?1
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