# Plant Protection Equipments - Sprayers - 2 Online Exam Quiz

Plant Protection Equipments - Sprayers - 2 GK Quiz. Question and Answers related to Plant Protection Equipments - Sprayers - 2. MCQ (Multiple Choice Questions with answers about Plant Protection Equipments - Sprayers - 2

Options

A : 44

B : 46

C : 48

D : 50

Options

A : 0.0135 l/s

B : 0.0136 l/s

C : 0.0137 l/s

D : 0.0138 l/s

### A hydraulic sprayer fitted with hollow nozzle is required to be calibrated for application rate 150 L/ha. The sprayer speed is 6.5 km/h. Nozzle spacing is 50 cm. The available 0.787 mm orifice diameter. Nozzle is rated at 0.473 L/min. What is the nozzle flow rate?

Options

A : 49.51 \frac{L}{h}

B : 54.44 \frac{L}{h}

C : 48.75 \frac{L}{h}

D : 24.10 \frac{L}{h} >>>>>

Options

A : 2 km/h

B : 5 km/h

C : 3 km/h

D : 4 km/h

Options

A : 10

B : 20

C : 30

D : 40

Options

A : 2.82%

B : 3.87%

C : 4.87%

D : 5.87%

### In which of the following method microorganisms do not grow on the surface of the media?

Options

B : Pour plate

C : Membrane filtration

D : Surface fermentation

### What is the formula used for calculating VMD, when pressure is less than 675 kPa?

Options

A : \frac{(VMD1)}{VMD2}=\Big\{(\frac{P1}{P2})^{\frac{2}{3}} \Big\}

B : \frac{(VMD1)}{VMD2}=\Big\{(\frac{P2}{P1})^{\frac{2}{3}} \Big\}

C : \frac{(VMD2)}{VMD1}=\Big\{(\frac{P1}{P2})^{\frac{2}{3}} \Big\}

D : \frac{(VMD2)}{VMD1}=\Big\{(\frac{P1}{P2})^{\frac{1}{3}} \Big\}

### What is the Nozzle Flow Rate (NFR)?

Options

A : NFR = application rate + area covered by single nozzle

B : NFR = application rate * area covered by single nozzle

C : NFR = application rate ? area covered by single nozzle

D : NFR = \frac{application \, rate}{area \, covered \, by \, single \, nozzle}

### What will be the diameter of base of a spray cone in a boom sprayer?

Options

A : D = 2h tan \frac{?}{2}

B : D = 2h/tan \frac{?}{2}

C : D = 2h + tan \frac{?}{2}

D : D = 2h ? tan \frac{?}{2}

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