High Performance Climb Online Exam Quiz

High Performance Climb GK Quiz. Question and Answers related to High Performance Climb. MCQ (Multiple Choice Questions with answers about High Performance Climb

In the case of cambered airfoil the value of ?0 is positive.

Options

A : TRUE

B : FALSE

C : -

D : -

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In transonic region the thrust is inversely proportional to drag.

Options

A : TRUE

B : FALSE

C : -

D : -

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The formula for SEP is given by ___

Options

A : [FN-D]\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}

B : [FN+D]\frac{V}{W}=\frac{d}{dt}\Big\{H+\frac{V^2}{2g}\Big\}

C : [FN-D]\frac{V}{W}=\frac{d}{dt}\Big\{H-\frac{V^2}{2g}\Big\}

D : [FN+D]\frac{V}{W}=\frac{d}{dt}\Big\{H-\frac{V^2}{2g}\Big\}

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The time taken to increase the specific total energy will be minimized by maximizing the SEP.

Options

A : TRUE

B : FALSE

C : -

D : -

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The zero-lift angle of attack is zero if the aerofoil is symmetric.

Options

A : TRUE

B : FALSE

C : -

D : -

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What are the methods followed to gain advantage in air to air combat mission?

Options

A : Accelerate to the operational height in a short time

B : Decelerate to the operational height in a short time

C : Accelerate to the operational height in a long time

D : Decelerate to the operational height in a long time

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What is the operational technique in combat mission aircraft?

Options

A : Minimizing the time required to increase the total energy of the aircraft to its combat height

B : Maximizing the time required to decrease the total energy of the aircraft to its combat height

C : Minimizing the time required to decrease the total energy of the aircraft to its combat height

D : Minimizing the time required to increase the total energy of the aircraft to its combat height

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What is the theoretical value of lift curve slope of a flat airfoil?

Options

A : 2? per radian

B : 4a? per radian

C : 3? per radian

D : ? per radian

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Which of the following is the correct formula for lift of an aircraft?

Options

A : L=\frac{1}{2}12 ?V2SCl

B : L=\frac{1}{2}V2SCl

C : L=\frac{1}{2}?V2Cl

D : L=\frac{1}{2}PV2SCl

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