Question: In the equation SQNR = 6.02b + 16.81 – 20log_{10} ?frac{R}{?_x}, for R = 6?x the equation becomes?
Options
A : SQNR = 6.02b-1.25 dB
B : SQNR = 6.87b-1.55 dB
C : SQNR = 6.02b+1.25 dB
D : SQNR = 6.87b+1.25 dB
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