Question: If the low pass filter described by the difference equation y(n)=0.9y(n-1)+0.1x(n) is converted into a high pass filter, then what is the frequency response of the high pass filter?
Options
A : 0.1/(1+0.9ej?)
B : 0.1/(1+0.9e-j?)
C : 0.1/(1-0.9ej?)
D : None of the mentioned
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