Antenna Noise Temperature Online Exam Quiz
Antenna Noise Temperature GK Quiz. Question and Answers related to Antenna Noise Temperature. MCQ (Multiple Choice Questions with answers about Antenna Noise Temperature
Effective noise temperature Te in terms of noise figure is __
Options
A : Te=To (F-1)
B : Te=To/(F-1)
C : Te=To/(F+1)
D : Te=To (F+1)
Expression for noise figure F related to the effective noise temperature Te is __
Options
A : F=1+\frac{T_e}{T_o}
B : F=1+\frac{T_0}{T_e}
C : F=1-\frac{T_e}{T_o}
D : F=1-\frac{T_0}{T_e}
Find the effective noise temperature if noise figure is 3 at room temperature (290K)?
Options
A : 290K
B : 580K
C : 289K
D : 195K
The induction and radiation fields are equal at a distance of ___
Options
A : ?/4
B : ?/6
C : ?/8
D : ?/2
The ratio of radiation intensity in a given direction from antenna to the radiation intensity over all directions is called as __
Options
A : Directivity
B : Radiation power density
C : Gain of antenna
D : Array Factor
The relation between vector magnetic potential and current density is given by __
Options
A : ?.A=J
B : ??A=H
C : ?2A=-?J
D : ?2A=??H
What is the overall efficiency of a lossless antenna with reflection coefficient 0.15?
Options
A : 0.997
B : 0.779
C : 0.669
D : 0.977
What is the relation between noise temperature introduced by beam TB and the antenna temperature TA when the solid angle obtained by the noise source is greater than antenna solid angle?
Options
A : TA= TB
B : TA > TB
C : TA < TB
D : TA ? TB
What should be the noise figure value at which the effective noise temperature equals to room temperature?
Options
A : 2
B : 1
C : 0
D : 1/T_(o )
Which expression suits best when the solid angle obtained by the noise source is less than antenna solid angle?
Options
A : PA ?A=PB ?B and ?TA=\frac{\Omega_B}{\Omega_A} T_B
B : PA ?B=PB ?A and ?TA=\frac{\Omega_B}{\Omega_A} T_B
C : ?TA=\frac{\Omega_A}{\Omega_B} T_B and PA ?B=PB ?A
D : ?TA=\frac{\Omega_A}{\Omega_B} T_B and PA ?A=PB ?B